Springs

Table of Contents

1. Spring Force

Consider a spring with negligible mass and natural length \(l_0\) displaced to a new length \(l\) by a block:

springs1.png

The point at which the head of the spring is at the natural length is called the equilibrium position. When the block moves away from this position, it experiences a spring force, which is a restoring force that points back to the equilibrium position of the spring.

1.1. Hooke’s Law

This spring force is given by Hooke’s law, which states:

\begin{align} \mathbf{F}_s = -k\mathbf{x} \end{align}

where \(k\) is the spring constant, and \(\mathbf{x}\) is the displacement vector that points in the direction of displacement and has magnitude \(l-l_0\). The spring constant also measures how “stiff” the spring is: the greater the spring constant, the more stiff the spring.

Example: Block on spring

Consider a hanging spring with natural length \(L_0\) that is extended to a new length \(L\) with a block of mass \(m\):

springs2.png

The origin is set at the equilibrium position of the spring. We want to determine the new length \(L\) after a block of mass \(m\) is placed on the end and is stationary.

For a stationary block, we know that \(F_\text{net} = 0\). Thus, by Hooke’s law and Newton’s 2nd law, we have:

\begin{align} mg - k(L-L_0) &= 0 \notag \\ k(L-L_0) &= mg \notag \\ L-L_0 &= \frac{mg}{k} \notag \\ L &= L_0 + \frac{mg}{k} \notag \end{align}

1.2. General Form

We can provide a general prescription for the spring force if we consider two vectors, \(\mathbf{r}_A\) which points from the origin to the fixed end of the spring, and \(\mathbf{r}\) which points from the origin to the free end of the spring. If \(l_0\) is the unstretched length of the spring, then we can write:

\begin{align} \boxed{\mathbf{F}_s = -k(\|\mathbf{r} - \mathbf{r}_A\| - l_0)\frac{\mathbf{r} - \mathbf{r}_A}{\|\mathbf{r} - \mathbf{r}_A\|}} \end{align}
Last modified: 2026-06-23 13:08